3.8.66 \(\int \frac {1}{x^2 (a+b x)^{3/2} (c+d x)^{5/2}} \, dx\)
Optimal. Leaf size=264 \[ \frac {(5 a d+3 b c) \tanh ^{-1}\left (\frac {\sqrt {c} \sqrt {a+b x}}{\sqrt {a} \sqrt {c+d x}}\right )}{a^{5/2} c^{7/2}}-\frac {d \sqrt {a+b x} \left (5 a^2 d^2-6 a b c d+9 b^2 c^2\right )}{3 a^2 c^2 (c+d x)^{3/2} (b c-a d)^2}-\frac {b (3 b c-a d)}{a^2 c \sqrt {a+b x} (c+d x)^{3/2} (b c-a d)}-\frac {d \sqrt {a+b x} \left (-15 a^3 d^3+31 a^2 b c d^2-9 a b^2 c^2 d+9 b^3 c^3\right )}{3 a^2 c^3 \sqrt {c+d x} (b c-a d)^3}-\frac {1}{a c x \sqrt {a+b x} (c+d x)^{3/2}} \]
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Rubi [A] time = 0.27, antiderivative size = 264, normalized size of antiderivative = 1.00,
number of steps used = 7, number of rules used = 5, integrand size = 22, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.227, Rules used =
{103, 152, 12, 93, 208} \begin {gather*} -\frac {d \sqrt {a+b x} \left (31 a^2 b c d^2-15 a^3 d^3-9 a b^2 c^2 d+9 b^3 c^3\right )}{3 a^2 c^3 \sqrt {c+d x} (b c-a d)^3}-\frac {d \sqrt {a+b x} \left (5 a^2 d^2-6 a b c d+9 b^2 c^2\right )}{3 a^2 c^2 (c+d x)^{3/2} (b c-a d)^2}+\frac {(5 a d+3 b c) \tanh ^{-1}\left (\frac {\sqrt {c} \sqrt {a+b x}}{\sqrt {a} \sqrt {c+d x}}\right )}{a^{5/2} c^{7/2}}-\frac {b (3 b c-a d)}{a^2 c \sqrt {a+b x} (c+d x)^{3/2} (b c-a d)}-\frac {1}{a c x \sqrt {a+b x} (c+d x)^{3/2}} \end {gather*}
Antiderivative was successfully verified.
[In]
Int[1/(x^2*(a + b*x)^(3/2)*(c + d*x)^(5/2)),x]
[Out]
-((b*(3*b*c - a*d))/(a^2*c*(b*c - a*d)*Sqrt[a + b*x]*(c + d*x)^(3/2))) - 1/(a*c*x*Sqrt[a + b*x]*(c + d*x)^(3/2
)) - (d*(9*b^2*c^2 - 6*a*b*c*d + 5*a^2*d^2)*Sqrt[a + b*x])/(3*a^2*c^2*(b*c - a*d)^2*(c + d*x)^(3/2)) - (d*(9*b
^3*c^3 - 9*a*b^2*c^2*d + 31*a^2*b*c*d^2 - 15*a^3*d^3)*Sqrt[a + b*x])/(3*a^2*c^3*(b*c - a*d)^3*Sqrt[c + d*x]) +
((3*b*c + 5*a*d)*ArcTanh[(Sqrt[c]*Sqrt[a + b*x])/(Sqrt[a]*Sqrt[c + d*x])])/(a^(5/2)*c^(7/2))
Rule 12
Int[(a_)*(u_), x_Symbol] :> Dist[a, Int[u, x], x] /; FreeQ[a, x] && !MatchQ[u, (b_)*(v_) /; FreeQ[b, x]]
Rule 93
Int[(((a_.) + (b_.)*(x_))^(m_)*((c_.) + (d_.)*(x_))^(n_))/((e_.) + (f_.)*(x_)), x_Symbol] :> With[{q = Denomin
ator[m]}, Dist[q, Subst[Int[x^(q*(m + 1) - 1)/(b*e - a*f - (d*e - c*f)*x^q), x], x, (a + b*x)^(1/q)/(c + d*x)^
(1/q)], x]] /; FreeQ[{a, b, c, d, e, f}, x] && EqQ[m + n + 1, 0] && RationalQ[n] && LtQ[-1, m, 0] && SimplerQ[
a + b*x, c + d*x]
Rule 103
Int[((a_.) + (b_.)*(x_))^(m_)*((c_.) + (d_.)*(x_))^(n_.)*((e_.) + (f_.)*(x_))^(p_.), x_Symbol] :> Simp[(b*(a +
b*x)^(m + 1)*(c + d*x)^(n + 1)*(e + f*x)^(p + 1))/((m + 1)*(b*c - a*d)*(b*e - a*f)), x] + Dist[1/((m + 1)*(b*
c - a*d)*(b*e - a*f)), Int[(a + b*x)^(m + 1)*(c + d*x)^n*(e + f*x)^p*Simp[a*d*f*(m + 1) - b*(d*e*(m + n + 2) +
c*f*(m + p + 2)) - b*d*f*(m + n + p + 3)*x, x], x], x] /; FreeQ[{a, b, c, d, e, f, n, p}, x] && LtQ[m, -1] &&
IntegerQ[m] && (IntegerQ[n] || IntegersQ[2*n, 2*p])
Rule 152
Int[((a_.) + (b_.)*(x_))^(m_)*((c_.) + (d_.)*(x_))^(n_)*((e_.) + (f_.)*(x_))^(p_)*((g_.) + (h_.)*(x_)), x_Symb
ol] :> Simp[((b*g - a*h)*(a + b*x)^(m + 1)*(c + d*x)^(n + 1)*(e + f*x)^(p + 1))/((m + 1)*(b*c - a*d)*(b*e - a*
f)), x] + Dist[1/((m + 1)*(b*c - a*d)*(b*e - a*f)), Int[(a + b*x)^(m + 1)*(c + d*x)^n*(e + f*x)^p*Simp[(a*d*f*
g - b*(d*e + c*f)*g + b*c*e*h)*(m + 1) - (b*g - a*h)*(d*e*(n + 1) + c*f*(p + 1)) - d*f*(b*g - a*h)*(m + n + p
+ 3)*x, x], x], x] /; FreeQ[{a, b, c, d, e, f, g, h, n, p}, x] && LtQ[m, -1] && IntegersQ[2*m, 2*n, 2*p]
Rule 208
Int[((a_) + (b_.)*(x_)^2)^(-1), x_Symbol] :> Simp[(Rt[-(a/b), 2]*ArcTanh[x/Rt[-(a/b), 2]])/a, x] /; FreeQ[{a,
b}, x] && NegQ[a/b]
Rubi steps
\begin {align*} \int \frac {1}{x^2 (a+b x)^{3/2} (c+d x)^{5/2}} \, dx &=-\frac {1}{a c x \sqrt {a+b x} (c+d x)^{3/2}}-\frac {\int \frac {\frac {1}{2} (3 b c+5 a d)+3 b d x}{x (a+b x)^{3/2} (c+d x)^{5/2}} \, dx}{a c}\\ &=-\frac {b (3 b c-a d)}{a^2 c (b c-a d) \sqrt {a+b x} (c+d x)^{3/2}}-\frac {1}{a c x \sqrt {a+b x} (c+d x)^{3/2}}-\frac {2 \int \frac {\frac {1}{4} (b c-a d) (3 b c+5 a d)+b d (3 b c-a d) x}{x \sqrt {a+b x} (c+d x)^{5/2}} \, dx}{a^2 c (b c-a d)}\\ &=-\frac {b (3 b c-a d)}{a^2 c (b c-a d) \sqrt {a+b x} (c+d x)^{3/2}}-\frac {1}{a c x \sqrt {a+b x} (c+d x)^{3/2}}-\frac {d \left (9 b^2 c^2-6 a b c d+5 a^2 d^2\right ) \sqrt {a+b x}}{3 a^2 c^2 (b c-a d)^2 (c+d x)^{3/2}}+\frac {4 \int \frac {-\frac {3}{8} (b c-a d)^2 (3 b c+5 a d)-\frac {1}{4} b d \left (9 b^2 c^2-6 a b c d+5 a^2 d^2\right ) x}{x \sqrt {a+b x} (c+d x)^{3/2}} \, dx}{3 a^2 c^2 (b c-a d)^2}\\ &=-\frac {b (3 b c-a d)}{a^2 c (b c-a d) \sqrt {a+b x} (c+d x)^{3/2}}-\frac {1}{a c x \sqrt {a+b x} (c+d x)^{3/2}}-\frac {d \left (9 b^2 c^2-6 a b c d+5 a^2 d^2\right ) \sqrt {a+b x}}{3 a^2 c^2 (b c-a d)^2 (c+d x)^{3/2}}-\frac {d \left (9 b^3 c^3-9 a b^2 c^2 d+31 a^2 b c d^2-15 a^3 d^3\right ) \sqrt {a+b x}}{3 a^2 c^3 (b c-a d)^3 \sqrt {c+d x}}-\frac {8 \int \frac {3 (b c-a d)^3 (3 b c+5 a d)}{16 x \sqrt {a+b x} \sqrt {c+d x}} \, dx}{3 a^2 c^3 (b c-a d)^3}\\ &=-\frac {b (3 b c-a d)}{a^2 c (b c-a d) \sqrt {a+b x} (c+d x)^{3/2}}-\frac {1}{a c x \sqrt {a+b x} (c+d x)^{3/2}}-\frac {d \left (9 b^2 c^2-6 a b c d+5 a^2 d^2\right ) \sqrt {a+b x}}{3 a^2 c^2 (b c-a d)^2 (c+d x)^{3/2}}-\frac {d \left (9 b^3 c^3-9 a b^2 c^2 d+31 a^2 b c d^2-15 a^3 d^3\right ) \sqrt {a+b x}}{3 a^2 c^3 (b c-a d)^3 \sqrt {c+d x}}-\frac {(3 b c+5 a d) \int \frac {1}{x \sqrt {a+b x} \sqrt {c+d x}} \, dx}{2 a^2 c^3}\\ &=-\frac {b (3 b c-a d)}{a^2 c (b c-a d) \sqrt {a+b x} (c+d x)^{3/2}}-\frac {1}{a c x \sqrt {a+b x} (c+d x)^{3/2}}-\frac {d \left (9 b^2 c^2-6 a b c d+5 a^2 d^2\right ) \sqrt {a+b x}}{3 a^2 c^2 (b c-a d)^2 (c+d x)^{3/2}}-\frac {d \left (9 b^3 c^3-9 a b^2 c^2 d+31 a^2 b c d^2-15 a^3 d^3\right ) \sqrt {a+b x}}{3 a^2 c^3 (b c-a d)^3 \sqrt {c+d x}}-\frac {(3 b c+5 a d) \operatorname {Subst}\left (\int \frac {1}{-a+c x^2} \, dx,x,\frac {\sqrt {a+b x}}{\sqrt {c+d x}}\right )}{a^2 c^3}\\ &=-\frac {b (3 b c-a d)}{a^2 c (b c-a d) \sqrt {a+b x} (c+d x)^{3/2}}-\frac {1}{a c x \sqrt {a+b x} (c+d x)^{3/2}}-\frac {d \left (9 b^2 c^2-6 a b c d+5 a^2 d^2\right ) \sqrt {a+b x}}{3 a^2 c^2 (b c-a d)^2 (c+d x)^{3/2}}-\frac {d \left (9 b^3 c^3-9 a b^2 c^2 d+31 a^2 b c d^2-15 a^3 d^3\right ) \sqrt {a+b x}}{3 a^2 c^3 (b c-a d)^3 \sqrt {c+d x}}+\frac {(3 b c+5 a d) \tanh ^{-1}\left (\frac {\sqrt {c} \sqrt {a+b x}}{\sqrt {a} \sqrt {c+d x}}\right )}{a^{5/2} c^{7/2}}\\ \end {align*}
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Mathematica [A] time = 0.58, size = 263, normalized size = 1.00 \begin {gather*} \frac {-\frac {d \sqrt {a+b x} \left (5 a^2 d^2-6 a b c d+9 b^2 c^2\right )}{a c (b c-a d)^2}+\frac {(c+d x) \left (\sqrt {a} \sqrt {c} d \sqrt {a+b x} \left (15 a^3 d^3-31 a^2 b c d^2+9 a b^2 c^2 d-9 b^3 c^3\right )+3 \sqrt {c+d x} (5 a d+3 b c) (b c-a d)^3 \tanh ^{-1}\left (\frac {\sqrt {c} \sqrt {a+b x}}{\sqrt {a} \sqrt {c+d x}}\right )\right )}{a^{3/2} c^{5/2} (b c-a d)^3}-\frac {3 b (a d-3 b c)}{a \sqrt {a+b x} (a d-b c)}-\frac {3}{x \sqrt {a+b x}}}{3 a c (c+d x)^{3/2}} \end {gather*}
Antiderivative was successfully verified.
[In]
Integrate[1/(x^2*(a + b*x)^(3/2)*(c + d*x)^(5/2)),x]
[Out]
((-3*b*(-3*b*c + a*d))/(a*(-(b*c) + a*d)*Sqrt[a + b*x]) - 3/(x*Sqrt[a + b*x]) - (d*(9*b^2*c^2 - 6*a*b*c*d + 5*
a^2*d^2)*Sqrt[a + b*x])/(a*c*(b*c - a*d)^2) + ((c + d*x)*(Sqrt[a]*Sqrt[c]*d*(-9*b^3*c^3 + 9*a*b^2*c^2*d - 31*a
^2*b*c*d^2 + 15*a^3*d^3)*Sqrt[a + b*x] + 3*(b*c - a*d)^3*(3*b*c + 5*a*d)*Sqrt[c + d*x]*ArcTanh[(Sqrt[c]*Sqrt[a
+ b*x])/(Sqrt[a]*Sqrt[c + d*x])]))/(a^(3/2)*c^(5/2)*(b*c - a*d)^3))/(3*a*c*(c + d*x)^(3/2))
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IntegrateAlgebraic [A] time = 0.31, size = 309, normalized size = 1.17 \begin {gather*} \frac {(5 a d+3 b c) \tanh ^{-1}\left (\frac {\sqrt {a} \sqrt {c+d x}}{\sqrt {c} \sqrt {a+b x}}\right )}{a^{5/2} c^{7/2}}+\frac {(a+b x)^{3/2} \left (-\frac {15 a^4 d^4 (c+d x)^2}{(a+b x)^2}+\frac {10 a^3 c d^4 (c+d x)}{a+b x}+\frac {36 a^3 b c d^3 (c+d x)^2}{(a+b x)^2}-\frac {18 a^2 b^2 c^2 d^2 (c+d x)^2}{(a+b x)^2}-\frac {24 a^2 b c^2 d^3 (c+d x)}{a+b x}+2 a^2 c^2 d^4-\frac {9 b^4 c^4 (c+d x)^2}{(a+b x)^2}+\frac {6 a b^4 c^3 (c+d x)^3}{(a+b x)^3}+\frac {12 a b^3 c^3 d (c+d x)^2}{(a+b x)^2}\right )}{3 a^2 c^3 (c+d x)^{3/2} (a d-b c)^3 \left (\frac {a (c+d x)}{a+b x}-c\right )} \end {gather*}
Antiderivative was successfully verified.
[In]
IntegrateAlgebraic[1/(x^2*(a + b*x)^(3/2)*(c + d*x)^(5/2)),x]
[Out]
((a + b*x)^(3/2)*(2*a^2*c^2*d^4 - (24*a^2*b*c^2*d^3*(c + d*x))/(a + b*x) + (10*a^3*c*d^4*(c + d*x))/(a + b*x)
- (9*b^4*c^4*(c + d*x)^2)/(a + b*x)^2 + (12*a*b^3*c^3*d*(c + d*x)^2)/(a + b*x)^2 - (18*a^2*b^2*c^2*d^2*(c + d*
x)^2)/(a + b*x)^2 + (36*a^3*b*c*d^3*(c + d*x)^2)/(a + b*x)^2 - (15*a^4*d^4*(c + d*x)^2)/(a + b*x)^2 + (6*a*b^4
*c^3*(c + d*x)^3)/(a + b*x)^3))/(3*a^2*c^3*(-(b*c) + a*d)^3*(c + d*x)^(3/2)*(-c + (a*(c + d*x))/(a + b*x))) +
((3*b*c + 5*a*d)*ArcTanh[(Sqrt[a]*Sqrt[c + d*x])/(Sqrt[c]*Sqrt[a + b*x])])/(a^(5/2)*c^(7/2))
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fricas [B] time = 13.49, size = 1658, normalized size = 6.28
result too large to display
Verification of antiderivative is not currently implemented for this CAS.
[In]
integrate(1/x^2/(b*x+a)^(3/2)/(d*x+c)^(5/2),x, algorithm="fricas")
[Out]
[1/12*(3*((3*b^5*c^4*d^2 - 4*a*b^4*c^3*d^3 - 6*a^2*b^3*c^2*d^4 + 12*a^3*b^2*c*d^5 - 5*a^4*b*d^6)*x^4 + (6*b^5*
c^5*d - 5*a*b^4*c^4*d^2 - 16*a^2*b^3*c^3*d^3 + 18*a^3*b^2*c^2*d^4 + 2*a^4*b*c*d^5 - 5*a^5*d^6)*x^3 + (3*b^5*c^
6 + 2*a*b^4*c^5*d - 14*a^2*b^3*c^4*d^2 + 19*a^4*b*c^2*d^4 - 10*a^5*c*d^5)*x^2 + (3*a*b^4*c^6 - 4*a^2*b^3*c^5*d
- 6*a^3*b^2*c^4*d^2 + 12*a^4*b*c^3*d^3 - 5*a^5*c^2*d^4)*x)*sqrt(a*c)*log((8*a^2*c^2 + (b^2*c^2 + 6*a*b*c*d +
a^2*d^2)*x^2 + 4*(2*a*c + (b*c + a*d)*x)*sqrt(a*c)*sqrt(b*x + a)*sqrt(d*x + c) + 8*(a*b*c^2 + a^2*c*d)*x)/x^2)
- 4*(3*a^2*b^3*c^6 - 9*a^3*b^2*c^5*d + 9*a^4*b*c^4*d^2 - 3*a^5*c^3*d^3 + (9*a*b^4*c^4*d^2 - 9*a^2*b^3*c^3*d^3
+ 31*a^3*b^2*c^2*d^4 - 15*a^4*b*c*d^5)*x^3 + (18*a*b^4*c^5*d - 15*a^2*b^3*c^4*d^2 + 33*a^3*b^2*c^3*d^3 + 11*a
^4*b*c^2*d^4 - 15*a^5*c*d^5)*x^2 + (9*a*b^4*c^6 - 3*a^2*b^3*c^5*d - 9*a^3*b^2*c^4*d^2 + 39*a^4*b*c^3*d^3 - 20*
a^5*c^2*d^4)*x)*sqrt(b*x + a)*sqrt(d*x + c))/((a^3*b^4*c^7*d^2 - 3*a^4*b^3*c^6*d^3 + 3*a^5*b^2*c^5*d^4 - a^6*b
*c^4*d^5)*x^4 + (2*a^3*b^4*c^8*d - 5*a^4*b^3*c^7*d^2 + 3*a^5*b^2*c^6*d^3 + a^6*b*c^5*d^4 - a^7*c^4*d^5)*x^3 +
(a^3*b^4*c^9 - a^4*b^3*c^8*d - 3*a^5*b^2*c^7*d^2 + 5*a^6*b*c^6*d^3 - 2*a^7*c^5*d^4)*x^2 + (a^4*b^3*c^9 - 3*a^5
*b^2*c^8*d + 3*a^6*b*c^7*d^2 - a^7*c^6*d^3)*x), -1/6*(3*((3*b^5*c^4*d^2 - 4*a*b^4*c^3*d^3 - 6*a^2*b^3*c^2*d^4
+ 12*a^3*b^2*c*d^5 - 5*a^4*b*d^6)*x^4 + (6*b^5*c^5*d - 5*a*b^4*c^4*d^2 - 16*a^2*b^3*c^3*d^3 + 18*a^3*b^2*c^2*d
^4 + 2*a^4*b*c*d^5 - 5*a^5*d^6)*x^3 + (3*b^5*c^6 + 2*a*b^4*c^5*d - 14*a^2*b^3*c^4*d^2 + 19*a^4*b*c^2*d^4 - 10*
a^5*c*d^5)*x^2 + (3*a*b^4*c^6 - 4*a^2*b^3*c^5*d - 6*a^3*b^2*c^4*d^2 + 12*a^4*b*c^3*d^3 - 5*a^5*c^2*d^4)*x)*sqr
t(-a*c)*arctan(1/2*(2*a*c + (b*c + a*d)*x)*sqrt(-a*c)*sqrt(b*x + a)*sqrt(d*x + c)/(a*b*c*d*x^2 + a^2*c^2 + (a*
b*c^2 + a^2*c*d)*x)) + 2*(3*a^2*b^3*c^6 - 9*a^3*b^2*c^5*d + 9*a^4*b*c^4*d^2 - 3*a^5*c^3*d^3 + (9*a*b^4*c^4*d^2
- 9*a^2*b^3*c^3*d^3 + 31*a^3*b^2*c^2*d^4 - 15*a^4*b*c*d^5)*x^3 + (18*a*b^4*c^5*d - 15*a^2*b^3*c^4*d^2 + 33*a^
3*b^2*c^3*d^3 + 11*a^4*b*c^2*d^4 - 15*a^5*c*d^5)*x^2 + (9*a*b^4*c^6 - 3*a^2*b^3*c^5*d - 9*a^3*b^2*c^4*d^2 + 39
*a^4*b*c^3*d^3 - 20*a^5*c^2*d^4)*x)*sqrt(b*x + a)*sqrt(d*x + c))/((a^3*b^4*c^7*d^2 - 3*a^4*b^3*c^6*d^3 + 3*a^5
*b^2*c^5*d^4 - a^6*b*c^4*d^5)*x^4 + (2*a^3*b^4*c^8*d - 5*a^4*b^3*c^7*d^2 + 3*a^5*b^2*c^6*d^3 + a^6*b*c^5*d^4 -
a^7*c^4*d^5)*x^3 + (a^3*b^4*c^9 - a^4*b^3*c^8*d - 3*a^5*b^2*c^7*d^2 + 5*a^6*b*c^6*d^3 - 2*a^7*c^5*d^4)*x^2 +
(a^4*b^3*c^9 - 3*a^5*b^2*c^8*d + 3*a^6*b*c^7*d^2 - a^7*c^6*d^3)*x)]
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giac [B] time = 13.28, size = 1336, normalized size = 5.06
result too large to display
Verification of antiderivative is not currently implemented for this CAS.
[In]
integrate(1/x^2/(b*x+a)^(3/2)/(d*x+c)^(5/2),x, algorithm="giac")
[Out]
-2/3*sqrt(b*x + a)*((11*b^6*c^6*d^5*abs(b) - 28*a*b^5*c^5*d^6*abs(b) + 23*a^2*b^4*c^4*d^7*abs(b) - 6*a^3*b^3*c
^3*d^8*abs(b))*(b*x + a)/(b^7*c^11*d - 5*a*b^6*c^10*d^2 + 10*a^2*b^5*c^9*d^3 - 10*a^3*b^4*c^8*d^4 + 5*a^4*b^3*
c^7*d^5 - a^5*b^2*c^6*d^6) + 6*(2*b^7*c^7*d^4*abs(b) - 7*a*b^6*c^6*d^5*abs(b) + 9*a^2*b^5*c^5*d^6*abs(b) - 5*a
^3*b^4*c^4*d^7*abs(b) + a^4*b^3*c^3*d^8*abs(b))/(b^7*c^11*d - 5*a*b^6*c^10*d^2 + 10*a^2*b^5*c^9*d^3 - 10*a^3*b
^4*c^8*d^4 + 5*a^4*b^3*c^7*d^5 - a^5*b^2*c^6*d^6))/(b^2*c + (b*x + a)*b*d - a*b*d)^(3/2) - 2*(3*sqrt(b*d)*b^9*
c^5 - 9*sqrt(b*d)*a*b^8*c^4*d + 12*sqrt(b*d)*a^2*b^7*c^3*d^2 - 10*sqrt(b*d)*a^3*b^6*c^2*d^3 + 5*sqrt(b*d)*a^4*
b^5*c*d^4 - sqrt(b*d)*a^5*b^4*d^5 - 6*sqrt(b*d)*(sqrt(b*d)*sqrt(b*x + a) - sqrt(b^2*c + (b*x + a)*b*d - a*b*d)
)^2*b^7*c^4 + 2*sqrt(b*d)*(sqrt(b*d)*sqrt(b*x + a) - sqrt(b^2*c + (b*x + a)*b*d - a*b*d))^2*a*b^6*c^3*d - 6*sq
rt(b*d)*(sqrt(b*d)*sqrt(b*x + a) - sqrt(b^2*c + (b*x + a)*b*d - a*b*d))^2*a^2*b^5*c^2*d^2 + 2*sqrt(b*d)*(sqrt(
b*d)*sqrt(b*x + a) - sqrt(b^2*c + (b*x + a)*b*d - a*b*d))^2*a^3*b^4*c*d^3 + 3*sqrt(b*d)*(sqrt(b*d)*sqrt(b*x +
a) - sqrt(b^2*c + (b*x + a)*b*d - a*b*d))^4*b^5*c^3 - sqrt(b*d)*(sqrt(b*d)*sqrt(b*x + a) - sqrt(b^2*c + (b*x +
a)*b*d - a*b*d))^4*a*b^4*c^2*d - sqrt(b*d)*(sqrt(b*d)*sqrt(b*x + a) - sqrt(b^2*c + (b*x + a)*b*d - a*b*d))^4*
a^2*b^3*c*d^2 + sqrt(b*d)*(sqrt(b*d)*sqrt(b*x + a) - sqrt(b^2*c + (b*x + a)*b*d - a*b*d))^4*a^3*b^2*d^3)/((a^2
*b^2*c^5*abs(b) - 2*a^3*b*c^4*d*abs(b) + a^4*c^3*d^2*abs(b))*(b^6*c^3 - 3*a*b^5*c^2*d + 3*a^2*b^4*c*d^2 - a^3*
b^3*d^3 - 3*(sqrt(b*d)*sqrt(b*x + a) - sqrt(b^2*c + (b*x + a)*b*d - a*b*d))^2*b^4*c^2 + 2*(sqrt(b*d)*sqrt(b*x
+ a) - sqrt(b^2*c + (b*x + a)*b*d - a*b*d))^2*a*b^3*c*d + (sqrt(b*d)*sqrt(b*x + a) - sqrt(b^2*c + (b*x + a)*b*
d - a*b*d))^2*a^2*b^2*d^2 + 3*(sqrt(b*d)*sqrt(b*x + a) - sqrt(b^2*c + (b*x + a)*b*d - a*b*d))^4*b^2*c + (sqrt(
b*d)*sqrt(b*x + a) - sqrt(b^2*c + (b*x + a)*b*d - a*b*d))^4*a*b*d - (sqrt(b*d)*sqrt(b*x + a) - sqrt(b^2*c + (b
*x + a)*b*d - a*b*d))^6)) + (3*sqrt(b*d)*b^3*c + 5*sqrt(b*d)*a*b^2*d)*arctan(-1/2*(b^2*c + a*b*d - (sqrt(b*d)*
sqrt(b*x + a) - sqrt(b^2*c + (b*x + a)*b*d - a*b*d))^2)/(sqrt(-a*b*c*d)*b))/(sqrt(-a*b*c*d)*a^2*b*c^3*abs(b))
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maple [B] time = 0.05, size = 1692, normalized size = 6.41
result too large to display
Verification of antiderivative is not currently implemented for this CAS.
[In]
int(1/x^2/(b*x+a)^(3/2)/(d*x+c)^(5/2),x)
[Out]
1/6*(15*ln((a*d*x+b*c*x+2*a*c+2*(a*c)^(1/2)*((b*x+a)*(d*x+c))^(1/2))/x)*x^3*a^5*d^6-9*ln((a*d*x+b*c*x+2*a*c+2*
(a*c)^(1/2)*((b*x+a)*(d*x+c))^(1/2))/x)*x^2*b^5*c^6-30*x^2*a^4*d^5*((b*x+a)*(d*x+c))^(1/2)*(a*c)^(1/2)-30*x^3*
a^3*b*d^5*((b*x+a)*(d*x+c))^(1/2)*(a*c)^(1/2)+36*x^2*b^4*c^4*d*((b*x+a)*(d*x+c))^(1/2)*(a*c)^(1/2)-40*x*a^4*c*
d^4*((b*x+a)*(d*x+c))^(1/2)*(a*c)^(1/2)+18*a^3*b*c^3*d^2*((b*x+a)*(d*x+c))^(1/2)*(a*c)^(1/2)-18*a^2*b^2*c^4*d*
((b*x+a)*(d*x+c))^(1/2)*(a*c)^(1/2)-36*ln((a*d*x+b*c*x+2*a*c+2*(a*c)^(1/2)*((b*x+a)*(d*x+c))^(1/2))/x)*x^4*a^3
*b^2*c*d^5+18*ln((a*d*x+b*c*x+2*a*c+2*(a*c)^(1/2)*((b*x+a)*(d*x+c))^(1/2))/x)*x^4*a^2*b^3*c^2*d^4+12*ln((a*d*x
+b*c*x+2*a*c+2*(a*c)^(1/2)*((b*x+a)*(d*x+c))^(1/2))/x)*x^4*a*b^4*c^3*d^3-6*ln((a*d*x+b*c*x+2*a*c+2*(a*c)^(1/2)
*((b*x+a)*(d*x+c))^(1/2))/x)*x^3*a^4*b*c*d^5-54*ln((a*d*x+b*c*x+2*a*c+2*(a*c)^(1/2)*((b*x+a)*(d*x+c))^(1/2))/x
)*x^3*a^3*b^2*c^2*d^4+48*ln((a*d*x+b*c*x+2*a*c+2*(a*c)^(1/2)*((b*x+a)*(d*x+c))^(1/2))/x)*x^3*a^2*b^3*c^3*d^3+1
5*ln((a*d*x+b*c*x+2*a*c+2*(a*c)^(1/2)*((b*x+a)*(d*x+c))^(1/2))/x)*x^3*a*b^4*c^4*d^2-57*ln((a*d*x+b*c*x+2*a*c+2
*(a*c)^(1/2)*((b*x+a)*(d*x+c))^(1/2))/x)*x^2*a^4*b*c^2*d^4+42*ln((a*d*x+b*c*x+2*a*c+2*(a*c)^(1/2)*((b*x+a)*(d*
x+c))^(1/2))/x)*x^2*a^2*b^3*c^4*d^2-6*ln((a*d*x+b*c*x+2*a*c+2*(a*c)^(1/2)*((b*x+a)*(d*x+c))^(1/2))/x)*x^2*a*b^
4*c^5*d-36*ln((a*d*x+b*c*x+2*a*c+2*(a*c)^(1/2)*((b*x+a)*(d*x+c))^(1/2))/x)*x*a^4*b*c^3*d^3+18*ln((a*d*x+b*c*x+
2*a*c+2*(a*c)^(1/2)*((b*x+a)*(d*x+c))^(1/2))/x)*x*a^3*b^2*c^4*d^2+12*ln((a*d*x+b*c*x+2*a*c+2*(a*c)^(1/2)*((b*x
+a)*(d*x+c))^(1/2))/x)*x*a^2*b^3*c^5*d-6*x*a*b^3*c^4*d*((b*x+a)*(d*x+c))^(1/2)*(a*c)^(1/2)+62*x^3*a^2*b^2*c*d^
4*((b*x+a)*(d*x+c))^(1/2)*(a*c)^(1/2)-18*x^3*a*b^3*c^2*d^3*((b*x+a)*(d*x+c))^(1/2)*(a*c)^(1/2)+22*x^2*a^3*b*c*
d^4*((b*x+a)*(d*x+c))^(1/2)*(a*c)^(1/2)+66*x^2*a^2*b^2*c^2*d^3*((b*x+a)*(d*x+c))^(1/2)*(a*c)^(1/2)-30*x^2*a*b^
3*c^3*d^2*((b*x+a)*(d*x+c))^(1/2)*(a*c)^(1/2)+78*x*a^3*b*c^2*d^3*((b*x+a)*(d*x+c))^(1/2)*(a*c)^(1/2)-18*x*a^2*
b^2*c^3*d^2*((b*x+a)*(d*x+c))^(1/2)*(a*c)^(1/2)+18*x*b^4*c^5*((b*x+a)*(d*x+c))^(1/2)*(a*c)^(1/2)-6*a^4*c^2*d^3
*((b*x+a)*(d*x+c))^(1/2)*(a*c)^(1/2)+6*a*b^3*c^5*((b*x+a)*(d*x+c))^(1/2)*(a*c)^(1/2)+15*ln((a*d*x+b*c*x+2*a*c+
2*(a*c)^(1/2)*((b*x+a)*(d*x+c))^(1/2))/x)*x^4*a^4*b*d^6-9*ln((a*d*x+b*c*x+2*a*c+2*(a*c)^(1/2)*((b*x+a)*(d*x+c)
)^(1/2))/x)*x^4*b^5*c^4*d^2-18*ln((a*d*x+b*c*x+2*a*c+2*(a*c)^(1/2)*((b*x+a)*(d*x+c))^(1/2))/x)*x^3*b^5*c^5*d+3
0*ln((a*d*x+b*c*x+2*a*c+2*(a*c)^(1/2)*((b*x+a)*(d*x+c))^(1/2))/x)*x^2*a^5*c*d^5+15*ln((a*d*x+b*c*x+2*a*c+2*(a*
c)^(1/2)*((b*x+a)*(d*x+c))^(1/2))/x)*x*a^5*c^2*d^4-9*ln((a*d*x+b*c*x+2*a*c+2*(a*c)^(1/2)*((b*x+a)*(d*x+c))^(1/
2))/x)*x*a*b^4*c^6+18*x^3*b^4*c^3*d^2*((b*x+a)*(d*x+c))^(1/2)*(a*c)^(1/2))/c^3/a^2/(a*c)^(1/2)/x/(a*d-b*c)^3/(
(b*x+a)*(d*x+c))^(1/2)/(d*x+c)^(3/2)/(b*x+a)^(1/2)
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maxima [F] time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \int \frac {1}{{\left (b x + a\right )}^{\frac {3}{2}} {\left (d x + c\right )}^{\frac {5}{2}} x^{2}}\,{d x} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
[In]
integrate(1/x^2/(b*x+a)^(3/2)/(d*x+c)^(5/2),x, algorithm="maxima")
[Out]
integrate(1/((b*x + a)^(3/2)*(d*x + c)^(5/2)*x^2), x)
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mupad [F] time = 0.00, size = -1, normalized size = -0.00 \begin {gather*} \int \frac {1}{x^2\,{\left (a+b\,x\right )}^{3/2}\,{\left (c+d\,x\right )}^{5/2}} \,d x \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
[In]
int(1/(x^2*(a + b*x)^(3/2)*(c + d*x)^(5/2)),x)
[Out]
int(1/(x^2*(a + b*x)^(3/2)*(c + d*x)^(5/2)), x)
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sympy [F] time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \int \frac {1}{x^{2} \left (a + b x\right )^{\frac {3}{2}} \left (c + d x\right )^{\frac {5}{2}}}\, dx \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
[In]
integrate(1/x**2/(b*x+a)**(3/2)/(d*x+c)**(5/2),x)
[Out]
Integral(1/(x**2*(a + b*x)**(3/2)*(c + d*x)**(5/2)), x)
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